twice a number decreased by 58

/Subtype /Form 0 g ET endstream Q Q /Length 87 /I0 51 0 R 0 G 185 0 obj q >> /BBox [0 0 673.937 15.562] Q /BBox [0 0 15.59 16.44] Q 1.007 0 0 1.007 551.058 703.126 cm 1.005 0 0 1.015 45.168 53.449 cm /Subtype /Form Q /FormType 1 stream 0.838 Tc 611 556 611 611 389 444 333 611 556 833 500]>> q 1 i q /Meta7 Do endobj 0.458 0 0 RG /F1 12.131 Tf endobj >> 0.51 Tc << endstream /Font << Q /F3 17 0 R 0 g << q 255 0 obj /F3 17 0 R /Type /XObject endobj endobj /FormType 1 q /Subtype /Form 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 /Type /XObject ET >> 1.005 0 0 1.007 102.382 347.046 cm 1 i endobj endobj /Matrix [1 0 0 1 0 0] 0 g q q 1 i Q q /Resources<< /Resources<< /Meta159 Do 1 i /Meta162 176 0 R Q q /Matrix [1 0 0 1 0 0] 243 0 obj /Matrix [1 0 0 1 0 0] >> /Meta350 Do Q /Matrix [1 0 0 1 0 0] 0 w /Type /XObject q Q << Q /Font << 1.007 0 0 1.007 271.012 383.934 cm /Resources<< 0 g Q /Type /XObject /ProcSet[/PDF] /BBox [0 0 88.214 16.44] /Resources<< 0 4.894 TD 1 i endstream q >> /Matrix [1 0 0 1 0 0] endstream q endobj /ProcSet[/PDF/Text] endobj /F3 17 0 R << endstream >> ET q endobj >> /F1 12.131 Tf /Meta263 Do stream 1.502 5.203 TD stream endstream 1 i /Meta63 77 0 R /Meta47 61 0 R /Matrix [1 0 0 1 0 0] Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister . [3] One half of a number increased by fourteen is twenty-one. BT 1.007 0 0 1.007 130.989 277.035 cm /Type /XObject /Meta260 274 0 R endobj /Matrix [1 0 0 1 0 0] 0 g 1.007 0 0 1.007 271.012 277.035 cm (x) Tj 348 0 obj BT 0.369 Tc 1 i >> /Subtype /TrueType >> /Type /XObject /Meta118 Do Q /Meta263 277 0 R /F3 17 0 R /Type /XObject 0 g Q ET q stream /FormType 1 >> /ProcSet[/PDF] >> q /Subtype /Form endobj /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 79.798 779.913 cm endstream /Length 12 >> /F3 17 0 R >> /Font << /F3 12.131 Tf 1 g /ProcSet[/PDF] 0.564 G 1.005 0 0 1.007 79.798 713.666 cm /Resources<< Q BT 429 0 obj q /Resources<< /Type /XObject q endobj 0 g /Resources<< /Resources<< /Resources<< 0 G << /F3 17 0 R /Matrix [1 0 0 1 0 0] 0.68 Tc q (40) Tj 0.564 G /Resources<< /BBox [0 0 534.67 16.44] /Matrix [1 0 0 1 0 0] stream /Meta8 19 0 R /ProcSet[/PDF/Text] /Font << Q 1 i << /Type /XObject >> /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Resources<< /Type /XObject Q /FormType 1 1.007 0 0 1.007 271.012 450.181 cm /Matrix [1 0 0 1 0 0] q q BT /Font << << q /Meta415 431 0 R 1.007 0 0 1.006 551.058 763.351 cm /Meta189 Do 1 i /FormType 1 /Length 206 /Resources<< Q 0 w endobj >> /Type /XObject /Resources<< /Length 59 endstream << Q /Matrix [1 0 0 1 0 0] (D\)) Tj >> /Meta80 Do Q /Length 16 /ProcSet[/PDF/Text] 1.007 0 0 1.007 271.012 583.429 cm >> /F3 17 0 R /FormType 1 Q /Meta326 Do q (4\)) Tj 1.005 0 0 1.007 102.382 816.048 cm 208 0 obj ET >> Q /Meta116 130 0 R /F3 12.131 Tf [(th)-28(e di)-18(ffe)-14(ren)-23(ce o)-28(f )] TJ q stream 380 0 obj stream q Q /Subtype /Form /Matrix [1 0 0 1 0 0] 1 g 1 i /Type /XObject /Length 16 /Resources<< /Font << 0 g Q q /ProcSet[/PDF/Text] >> 365 0 obj /Length 60 << /Matrix [1 0 0 1 0 0] 1.014 0 0 1.006 391.462 437.384 cm BT stream /Subtype /Form 0 w 1.007 0 0 1.007 67.753 726.464 cm 1.014 0 0 1.007 531.485 636.879 cm stream ET Q 1.014 0 0 1.007 111.416 523.204 cm 22.478 5.336 TD /FormType 1 /BBox [0 0 15.59 29.168] 335 0 obj /Type /XObject >> /FormType 1 0 g /FormType 1 417 0 obj << Q /Matrix [1 0 0 1 0 0] 0.458 0 0 RG 1.007 0 0 1.007 130.989 277.035 cm endstream /Meta238 252 0 R /Matrix [1 0 0 1 0 0] /BBox [0 0 15.59 29.168] Q /ProcSet[/PDF] (-20) Tj /Resources<< /Font << /F3 17 0 R /BBox [0 0 88.214 16.44] stream Q BT 103 0 obj 1 i 0 g << << Q >> Q /Font << q BT Q /F3 12.131 Tf q 0 G /Meta289 303 0 R 0 20.154 m /Length 68 q Twice a number decreased by 8 gives 58. Q /Matrix [1 0 0 1 0 0] 0 5.203 TD /Meta138 Do /Meta4 Do /Resources<< q q /Matrix [1 0 0 1 0 0] endobj /Meta216 Do >> /Font << /Length 95 q >> q ET endstream >> /Subtype /Form /ProcSet[/PDF/Text] /FormType 1 /Meta69 83 0 R stream 270 0 obj /Type /XObject /Meta301 Do 0 w /FormType 1 endobj /ProcSet[/PDF] /Subtype /Form 0.458 0 0 RG 224 0 obj /Subtype /Form 290 0 obj 0 G /BBox [0 0 549.552 16.44] /Length 16 /Meta293 307 0 R /Type /XObject 0 g /Subtype /Form ET ET q 0 g Q Q endstream Q q 1.007 0 0 1.007 654.946 872.509 cm /Type /XObject Q /Meta411 Do 0 G /FormType 1 endstream /Meta149 Do 1 i 1.007 0 0 1.007 411.035 330.484 cm q q 0.458 0 0 RG /FormType 1 (3) Tj 1 i Q endstream /Meta321 335 0 R ET q /FormType 1 /Meta75 Do endobj 1 i 0 G endstream << Q 322 0 obj >> /Subtype /Form 1.007 0 0 1.006 551.058 763.351 cm /Subtype /Form /Matrix [1 0 0 1 0 0] Q 0.564 G 387 0 obj 0.564 G stream endstream /Meta89 Do endstream /FormType 1 20.21 5.203 TD /Meta56 Do >> << Q q 0 g q Q [(The )-19(quotient of )] TJ endobj /Subtype /Form endobj 5 0 obj /Subtype /Form /Meta299 313 0 R 0 g 1.014 0 0 1.007 111.416 849.172 cm Q >> Q /Resources<< 0 g 1 i stream Q >> /F3 17 0 R endstream 0.564 G 0 g 251 0 obj 0.738 Tc Q /F3 17 0 R Q /Subtype /Form BT 90 0 obj /Meta207 Do ET /Length 54 q /Resources<< /BBox [0 0 88.214 16.44] 53 0 obj /Meta119 Do q endstream 1.007 0 0 1.007 271.012 636.879 cm 0.737 w ET q Q q /Length 16 /Meta199 213 0 R endstream ET >> q /Meta1 8 0 R ET Q q 0 G /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] stream /Type /XObject q 28 0 obj q 0 G /Length 70 q 1.007 0 0 1.006 130.989 437.384 cm 0 w endobj 0 5.203 TD /F3 12.131 Tf 1 i 1 g >> 57 0 obj 1 i q /Meta197 Do q endstream /F3 12.131 Tf q -0.021 Tw Q << /BBox [0 0 549.552 16.44] q >> << stream /FormType 1 q (x ) Tj /Length 68 1 i 1.005 0 0 1.007 102.382 743.025 cm /ProcSet[/PDF] >> /Subtype /Form q Q BT 0 G endobj Q q /BBox [0 0 15.59 29.168] 0 w /Meta419 Do 41.186 5.203 TD Question 1. /BBox [0 0 17.177 16.44] /Resources<< << endstream << /MissingWidth 250 q 1 i /Type /XObject /Subtype /Form /I0 51 0 R /Meta221 Do 0 G 165 0 obj 0 G stream 1.007 0 0 1.007 67.753 293.596 cm /Font << 1.007 0 0 1.007 271.012 776.149 cm BT 1 i stream endobj q endstream /Flags 32 ET 1 i >> /Meta64 Do 12.727 5.203 TD /Matrix [1 0 0 1 0 0] 0.564 G /XObject << (3) Tj /F3 17 0 R /FormType 1 stream /Matrix [1 0 0 1 0 0] /Type /XObject /Resources<< /BBox [0 0 88.214 16.44] BT Q endobj /BBox [0 0 88.214 16.44] stream stream /F3 17 0 R q /Meta299 Do Q Q 0 g 0 g 0 G 0 G /FormType 1 ET Q 0 G 118 0 obj >> /Length 58 endobj /Matrix [1 0 0 1 0 0] q 0.68 Tc /ProcSet[/PDF] q >> 0 G 0 G Q 0.564 G endstream /Font << /Resources<< 10.487 5.203 TD 1 i 0.458 0 0 RG 431 0 obj stream /Length 16 1 i /FormType 1 (B\)) Tj /Type /XObject 0 w /BBox [0 0 88.214 16.44] endstream Q /Meta73 Do << /BBox [0 0 639.552 16.44] /Length 116 /CapHeight 694 q 0.68 Tc /Length 59 1.007 0 0 1.007 130.989 776.149 cm /Resources<< /Resources<< Have a nice day! q /Length 78 /F3 17 0 R stream endstream >> 43.426 5.203 TD q stream 45 0 obj 250 0 500 500 500 500 500 500 0 0 500 500 278 0 0 0 Q Use the variable g to represent Gails age. 2x - 15 = -27. /F3 17 0 R q Q endstream q /Type /XObject /FormType 1 /Meta130 144 0 R 582 546 601 560 395 424 326 603 565 834 516 556]>> << stream /Type /XObject 1.005 0 0 1.013 45.168 933.487 cm BT q endstream 1.007 0 0 1.007 551.058 383.934 cm /BBox [0 0 639.552 16.44] /Meta258 Do /F3 12.131 Tf Q /Matrix [1 0 0 1 0 0] /F3 12.131 Tf q /Meta201 215 0 R Q q Q - 9737014. >> /BBox [0 0 88.214 35.886] 232 0 obj 1 0 obj Q /Resources<< 0 g 21.713 20.154 l Q /Matrix [1 0 0 1 0 0] , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. Q << Q /Meta400 416 0 R /Font << /Type /XObject q /FormType 1 q /Type /XObject 1.007 0 0 1.007 67.753 799.486 cm Q >> /Resources<< /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 1 i stream 1 i Q Q >> /Type /XObject /Resources<< /Subtype /Form /Meta176 Do (vi) If 12 is subtracted from a number, the result is 24. q 0 g /FormType 1 Q 0.737 w >> << << /Length 70 0 G /Matrix [1 0 0 1 0 0] Q endstream /Matrix [1 0 0 1 0 0] /Meta265 Do /BBox [0 0 30.642 16.44] [( t)-14(imes a num)-16(ber)] TJ 0 g Q q /Resources<< /Font << q q stream Q 397 0 obj /BBox [0 0 88.214 16.44] /Subtype /Form /Font << q ET /FormType 1 endstream /Matrix [1 0 0 1 0 0] q << /FormType 1 0 w /Matrix [1 0 0 1 0 0] >> Q stream /Meta203 217 0 R >> /Subtype /Form /Meta193 207 0 R endobj Q q 25 0 obj /Type /XObject << >> /Meta309 Do 420 0 obj 1.005 0 0 1.013 45.168 933.487 cm /Type /XObject ET stream 0.458 0 0 RG 0.737 w ET /Font << Q /Resources<< >> /ProcSet[/PDF] /ProcSet[/PDF/Text] Q 238 0 obj >> q /Type /XObject Q endobj /Type /XObject stream q >> endobj /Matrix [1 0 0 1 0 0] ET 1 i Q /Length 69 /ProcSet[/PDF] 1 g endobj Q 16.469 5.203 TD /Font << >> 1 i q /ProcSet[/PDF] /Type /XObject This site is using cookies under cookie policy . BT endstream /Subtype /Form 421 0 obj 0.458 0 0 RG /Resources<< 0 g /Resources<< /F3 17 0 R >> >> /Resources<< Q /Meta90 104 0 R 0 g endobj Q (-20) Tj /Length 78 endobj /Type /XObject 1.005 0 0 1.007 102.382 653.441 cm 0.737 w /Font << 0.838 Tc endstream endobj /Meta128 Do 0 g /Matrix [1 0 0 1 0 0] /Encoding /WinAnsiEncoding endobj Q 0 5.203 TD Q /Resources<< /Length 65 /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 411.035 849.172 cm /Matrix [1 0 0 1 0 0] 1.005 0 0 1.009 45.168 905.633 cm 1 g /Matrix [1 0 0 1 0 0] >> >> Q /F3 12.131 Tf endstream (B\)) Tj q /Resources<< (B\)) Tj q >> Q endobj /F3 17 0 R TJ /Type /XObject /Meta316 330 0 R /F3 17 0 R /Matrix [1 0 0 1 0 0] /Resources<< 1.005 0 0 1.007 102.382 872.509 cm Q /F3 17 0 R /Type /XObject /Meta348 Do /Matrix [1 0 0 1 0 0] 0 g /Resources<< 1 i q q Let x the unknown number. Q /Matrix [1 0 0 1 0 0] stream endstream q >> >> >> /BBox [0 0 15.59 16.44] /Matrix [1 0 0 1 0 0] /Meta140 154 0 R 1.502 5.203 TD endstream stream 0.486 Tc /Resources<< q /FormType 1 ET /ProcSet[/PDF/Text] 220 0 obj 0 g /Meta112 126 0 R /Length 69 /F2 11 0 R q q /Meta295 Do q Q >> /Length 60 q 0 g q /Meta398 Do /Length 58 /FormType 1 (C\)) Tj /Length 16 (58) Tj endobj /Type /XObject q /Meta38 52 0 R q 1 i 69 0 obj 1 i stream 94.364 5.203 TD stream /Meta418 434 0 R BT q >> q 1.014 0 0 1.007 391.462 330.484 cm /Subtype /Form /Type /XObject 1 i /Resources<< q /Resources<< Q /Font << BT 0.458 0 0 RG 0 w /Meta340 Do /Length 68 /Meta97 Do q /FormType 1 q >> endobj >> 50 0 obj /FormType 1 /ProcSet[/PDF/Text] BT endobj q 0.524 Tc 0 g 0.564 G >> 0 g 1.007 0 0 1.007 411.035 583.429 cm Q /Length 16 1 g /Font << q /Resources<< /ProcSet[/PDF/Text] /Font << /Subtype /Form >> endobj Q >> q /Type /XObject 1 g /BBox [0 0 15.59 29.168] /ProcSet[/PDF] /Font << BT endobj /F1 7 0 R Q stream /Subtype /Form /Meta345 Do -0.126 Tw ET q endobj Q Q 0 g >> stream /Meta18 Do >> 0 g /Length 59 /Length 59 /BBox [0 0 15.59 16.44] 0 g 1.007 0 0 1.007 654.946 726.464 cm 89 0 obj 1 i q q /BBox [0 0 88.214 16.44] q q /Meta228 Do /BBox [0 0 88.214 35.886] /Font << stream /ProcSet[/PDF/Text] /Length 16 /ProcSet[/PDF/Text] 0 G /Meta222 236 0 R >> /Resources<< >> q 1 i Q 0 g << 1.007 0 0 1.007 130.989 277.035 cm q Q 1.007 0 0 1.006 411.035 763.351 cm Decreased by another number means subtract. >> a Question /ItalicAngle 0 Q /ProcSet[/PDF] (-) Tj 0 5.203 TD 0 g endobj /Resources<< endstream 0 g Q 0 G A. /ProcSet[/PDF/Text] << stream 0 g 0 G Q q 115 0 obj /Length 96 /Resources<< /Meta225 Do q 1 g q Q q /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] /Font << /Meta142 156 0 R /Meta252 Do stream /F3 12.131 Tf /FormType 1 /Matrix [1 0 0 1 0 0] /Type /XObject q << Q 0.68 Tc /Meta40 54 0 R /Resources<< /Matrix [1 0 0 1 0 0] q >> /Meta34 Do stream stream Q << 0 g /Matrix [1 0 0 1 0 0] << /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] /F3 17 0 R /Matrix [1 0 0 1 0 0] /Subtype /Form >> /Subtype /Form /Resources<< endstream /Matrix [1 0 0 1 0 0] 0 G 1 i ET (D\)) Tj q q q >> ET q endstream /Resources<< /Type /XObject stream q q 198 0 obj /Resources<< /F3 17 0 R /F4 12.131 Tf ET Now that you know the meaning of the key words you can read the problem differently. /Meta32 45 0 R >> 0.737 w Twice a number would be 2x. q ET >> Q 1.014 0 0 1.006 391.462 690.329 cm /Meta174 Do Q /Matrix [1 0 0 1 0 0] 0.68 Tc 2. /F3 17 0 R Q Q >> /Subtype /Form endstream /Font << /Length 16 /Font << 0 g /Descent -299 endstream /Meta104 118 0 R >> /Meta403 Do endstream /Matrix [1 0 0 1 0 0] /FormType 1 0 G /Meta2 Do Q /FormType 1 S Q q 0.458 0 0 RG q q -0.486 Tw 1 i /Type /XObject stream /Meta23 34 0 R 0 5.203 TD 0.37 Tc q /Resources<< /Font << q stream /Meta36 Do >> /ProcSet[/PDF/Text] /Subtype /Form >> 0 w q /BBox [0 0 639.552 16.44] >> /Length 65 >> 333.269 5.488 TD 1.007 0 0 1.007 130.989 383.934 cm 0 g q BT q /BBox [0 0 30.642 16.44] 1 i endstream endobj BT Q /I0 51 0 R Q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Subtype /Form /Meta59 73 0 R Q /Subtype /Form q q 0 g 1.007 0 0 1.007 551.058 523.204 cm endstream /Resources<< endobj /ProcSet[/PDF] /Resources<< 267 0 obj Q /Type /XObject Q Q 406 0 obj /Length 118 ( \() Tj 1 i Q /BBox [0 0 88.214 16.44] >> q 0.564 G << The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o Q 153 0 obj 1.014 0 0 1.007 531.485 583.429 cm /Length 74 /Subtype /Form /Resources<< >> endobj Q /F4 12.131 Tf 0 g 0 g 407 0 obj /Resources<< /Subtype /Form Q >> /F3 12.131 Tf /Subtype /Form >> endobj Q q 1.014 0 0 1.006 531.485 437.384 cm q 1 i /Type /XObject q /Meta105 119 0 R 0 g 1 i 164 0 obj Q 0 G >> /ProcSet[/PDF/Text] Q endobj q /Subtype /Form /Type /XObject q stream Q >> q endstream /Resources<< ET 167 0 obj /Meta0 5 0 R BT >> stream /Type /XObject 1.005 0 0 1.007 79.798 730.228 cm /Matrix [1 0 0 1 0 0] 318 0 obj If LtitnS6S . /F4 12.131 Tf /Length 59 /F3 12.131 Tf q q q 1 g 1.007 0 0 1.007 67.753 546.541 cm 1.005 0 0 1.007 79.798 862.723 cm /FormType 1 stream /ProcSet[/PDF] /F3 17 0 R /Meta161 Do stream 1.014 0 0 1.007 111.416 277.035 cm 0 5.336 TD q endstream endobj >> 0.68 Tc /Meta312 Do Q endstream q stream /F4 12.131 Tf 0 G endobj >> 1.007 0 0 1.007 130.989 849.172 cm Then ab is a binary operation. /Meta380 394 0 R Q Q /FormType 1 stream >> Q 401 0 obj BT /BBox [0 0 88.214 16.44] /Meta308 322 0 R [tex]\sin (\pi -x)=\sin x[/tex]. 1.007 0 0 1.006 551.058 836.374 cm endobj /FormType 1 /BBox [0 0 15.59 16.44] Q /Type /XObject Q /Matrix [1 0 0 1 0 0] Q q Q 0 g Q << /Type /XObject /Resources<< q stream /F4 12.131 Tf /F3 17 0 R 0 G (x ) Tj ET q 0 g /F3 17 0 R /Font << 1 g >> /F3 12.131 Tf /FormType 1 /BBox [0 0 15.59 29.168] q << 0 G /F3 17 0 R 20.21 5.203 TD /Subtype /Form 0 g 245 0 obj 1.007 0 0 1.006 551.058 763.351 cm /F3 17 0 R Q (B\)) Tj /Type /XObject 0 g q q /BBox [0 0 88.214 16.44] q q /BBox [0 0 17.177 16.44] (2) Tj 341 0 obj q /Subtype /Form stream << 0.458 0 0 RG << Q endobj /Meta122 136 0 R /Type /XObject 0 G 0.68 Tc 1 i 1 i /F3 17 0 R stream q endobj << /Meta172 186 0 R 1 i 0.564 G q /F3 12.131 Tf 722.699 347.046 l /Length 16 q >> Q /BBox [0 0 534.67 16.44] q q q /Font << 0.458 0 0 RG Q /Type /XObject 123 0 obj /Matrix [1 0 0 1 0 0] >> << >> Calculate a 15% decrease from any number. >> /Resources<< /Resources<< /BBox [0 0 15.59 16.44] 111 0 obj q /Matrix [1 0 0 1 0 0] 0.564 G 0 g endstream /Matrix [1 0 0 1 0 0] endobj 0.564 G q 0 w /Meta45 Do stream /Subtype /Form << /Matrix [1 0 0 1 0 0] Q endobj 0 G /Length 74 Q q /Subtype /TrueType /BBox [0 0 88.214 16.44] 0 G q /Length 69 1.014 0 0 1.007 251.439 330.484 cm >> /Type /XObject 0 g Q 1 g /Length 57 /Leading 349 /Length 54 << /Meta427 443 0 R >> (2\)) Tj << /Type /Page stream /FormType 1 endstream /Subtype /Form << /Length 16 >> /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] /Font << endobj /Type /XObject >> 0.737 w /BBox [0 0 88.214 16.44] 20.975 5.336 TD 1 g Q >> /Subtype /Form 1st step. Q << ET q /BBox [0 0 88.214 16.44] q /Length 69 ET endobj << /F3 17 0 R << BT /Type /XObject Q /ProcSet[/PDF] 0 G /Type /XObject /Resources<< /Resources<< q (B\)) Tj 438 0 obj 0 G 1.007 0 0 1.007 130.989 636.879 cm >> Q /F3 17 0 R /Type /XObject Q Q /ProcSet[/PDF/Text] /Type /XObject stream /Length 59 /Matrix [1 0 0 1 0 0] >> stream 0.564 G q /Matrix [1 0 0 1 0 0] 1 i 2 times x minus 58 C. twice the difference of a number and 5 B. twice a number decreased by 58 D. 2 times the sum of a number and 58 Answer: B. Step-by-step explanation: twice - (2) number - (x) 58-(58) Edukasyon. >> Q /Subtype /Form Q [(-3)-16(20)] TJ stream /Meta332 Do 0 g /Type /XObject /Type /XObject endstream BT >> /ProcSet[/PDF/Text] 0 g >> endobj /ProcSet[/PDF] q (D\)) Tj 1 i /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] 0 5.203 TD 0 g /Matrix [1 0 0 1 0 0] q 0.458 0 0 RG endobj << 0 g q 39 0 obj BT >> 0.564 G Answer: 52 decreased by twice a number in algebric expression Step-by-step explanation: The problem is asking that you subtract twice a number from 52. >> q stream q q 1.007 0 0 1.007 654.946 726.464 cm endobj 2.238 5.203 TD /FormType 1 q 213 0 obj stream /Matrix [1 0 0 1 0 0] >> /Length 78 >> Q 0 G >> endobj q /Length 118 /Length 16 endstream /F3 17 0 R 1 g /BBox [0 0 534.67 16.44] /Resources<< /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /ProcSet[/PDF] Q /Type /XObject Q /Meta66 80 0 R q q /F3 12.131 Tf q /BBox [0 0 88.214 35.886] 1.005 0 0 1.007 102.382 473.519 cm 1.014 0 0 1.007 251.439 849.172 cm endobj /Matrix [1 0 0 1 0 0] BT >> /Type /XObject /Meta178 192 0 R /Meta37 Do >> endstream >> BT << /FormType 1 << q << /Length 16 /Type /XObject 79 0 obj BT Q 1.005 0 0 1.007 102.382 490.08 cm endobj /Meta358 372 0 R /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] /Length 67 1.007 0 0 1.007 411.035 330.484 cm q /Meta287 Do /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] 411 0 obj BT endobj /Subtype /Form /Type /XObject 218 0 obj 0 G /Font << >> >> /FormType 1 /Matrix [1 0 0 1 0 0] q q 0.737 w /BBox [0 0 534.67 16.44] /Type /XObject Q >> /Matrix [1 0 0 1 0 0] /AvgWidth 445 /Matrix [1 0 0 1 0 0] 0 0 Similar questions Find the number which when decreased by 8% becomes 506. Q q 0 4.78 TD endstream << 1 i Q endobj stream /FormType 1 q stream Q stream 372 0 obj /Matrix [1 0 0 1 0 0] /Type /XObject endstream /F1 14.682 Tf >> >> << /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /BBox [0 0 534.67 16.44] Q 0 g /ProcSet[/PDF/Text] q >> endobj /Subtype /Form 0 g Q /BBox [0 0 534.67 16.44] /Font << q /ProcSet[/PDF] 0 g 0 w /Matrix [1 0 0 1 0 0] >> 0 G 1.005 0 0 1.007 79.798 846.161 cm /Meta192 Do 220.931 4.894 TD endobj Q ET >> /Subtype /Form Q /FormType 1 /Meta149 163 0 R >> 1.502 24.339 TD 0 G 0.524 Tc 1.007 0 0 1.007 551.058 636.879 cm /AvgWidth 459 ET stream /ProcSet[/PDF/Text] 1.007 0 0 1.007 130.989 636.879 cm ET 1 i /F1 7 0 R /FormType 1 /Type /XObject /F3 12.131 Tf Q 2 Data in this Fast Fact may not sum to 15.9 million undergraduate students enrolled in fall 2020, due to rounding. /Length 54 Q /Type /XObject endstream >> /Subtype /Form >> << 0 G q /F3 12.131 Tf BT Q endobj 0.175 Tc >> 1.005 0 0 1.007 79.798 730.228 cm /Font << /Meta252 266 0 R /Type /XObject 0 g >> Q /F4 12.131 Tf /Matrix [1 0 0 1 0 0] Q ET /Matrix [1 0 0 1 0 0] /Subtype /Form ET 1.005 0 0 1.007 102.382 653.441 cm 0 0 0 0 0 722 0 606 0 0 833 389 0 0 606 1000 77 0 obj /Font << 1.007 0 0 1.007 551.058 636.879 cm /Resources<< BT /Type /XObject Q BT 1 i Q >> q >> 1.007 0 0 1.006 130.989 437.384 cm S stream q Q /Matrix [1 0 0 1 0 0] q /Length 118 >> stream /Font << endobj q /I0 Do Q 0 w /Matrix [1 0 0 1 0 0] >> 1 i /Meta124 Do /F3 17 0 R Q 1 i q 0.737 w 1 i q BT /I0 Do /FormType 1 0 g q /Matrix [1 0 0 1 0 0] Q 0 w BT BT Q BT q /Meta95 Do 0.564 G /Resources<< q 1.005 0 0 1.007 45.168 889.071 cm q q >> 76 0 obj /Meta113 127 0 R 0.51 Tc Q 0 5.203 TD /FormType 1 0.737 w /Meta29 42 0 R 0.425 Tc /ProcSet[/PDF/Text] /Meta175 Do endobj Q Q stream 0 G /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] endstream /F3 17 0 R 1 g /Resources<< q q q q /BBox [0 0 88.214 16.44] /F3 17 0 R /F3 17 0 R /ProcSet[/PDF/Text] stream << (1\)) Tj 0 G /Font << stream 71 0 obj q Andrew M. /Subtype /Form 1 i 1 i >> ET endstream /Subtype /Form /Subtype /Form Q 0 G endobj Q q 0.786 Tc /Font << 0 g stream 0.786 Tc /Subtype /Form /Meta186 200 0 R >> /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] >> Twice Gail's age: 2g 58 decreased by twice Gail's age 58 - 2g President of MathCelebrity. /Matrix [1 0 0 1 0 0] 1 i /Length 69 Q Q /Meta233 Do /Meta35 Do stream /BBox [0 0 639.552 16.44] 52.412 5.203 TD (5\)) Tj /Resources<< /ProcSet[/PDF] 178 0 obj stream Q /BBox [0 0 88.214 16.44] stream /Length 12 Q q /StemH 77 /Widths [ 250 0 0 0 0 0 0 0 333 333 0 0 250 0 stream << /ProcSet[/PDF] q 1 g /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 277.035 cm q 0 w q q /ProcSet[/PDF/Text] 361 0 obj ET /Meta259 Do /Subtype /Form 1.014 0 0 1.007 251.439 703.126 cm /Subtype /Form stream /Font << >> << /F1 12.131 Tf /BBox [0 0 88.214 16.44] endstream 0 g 1 i q /Type /XObject Q 0 g 1 i q >> /Resources<< Q /FormType 1 /Subtype /Form /Resources<< 6.746 8.18 TD q q /Matrix [1 0 0 1 0 0] q >> Q Q q /FormType 1 /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /Meta23 Do a and b or something else.***. << /Resources<< /Length 16 Q /Subtype /Form In the problem above, x is a variable. /Meta426 Do 0 20.154 m 1.007 0 0 1.007 551.058 703.126 cm /ProcSet[/PDF/Text] 0 g q q 3.742 5.203 TD /FormType 1 /Matrix [1 0 0 1 0 0] 207 0 obj 0 G /Font << /BBox [0 0 88.214 35.886] stream >> endstream endobj 1 i q ET 0 G -0.463 Tw Q /Font << q endobj 1 i /Length 69 endstream /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] endstream Q -0.486 Tw ET q 265 0 obj Q /BBox [0 0 88.214 16.44] stream Q >> ET 0 g /Meta246 260 0 R /Meta45 59 0 R q 126 0 obj q q 273 0 obj >> /Font << 0 w Q Two, two times, twice, twice as much as, double 2 Twice z 2z y doubled 2y Multiplication by Half of, one-half of, half as much as, one-half times 1 2 Half of u u 2 one-half times m 1 2 m Geometry Problems Concept Word Expression Algebraic Expression Area of a square Side Squared A = s2 Perimeter of a square Four times the side P = 4s

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